document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92604>Question 92604</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular garden is 1 ft less than 2 times its width.  If the perimeter of the garden is 46 ft, find the dimensions of the garden. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67419 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length of the garden be x ft and the width be y ft.\r<BR>\n" );
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document.write( "2 times width = 2y ft.<BR>\n" );
document.write( "1 ft less than 2 times width = (2y - 1) ft.<BR>\n" );
document.write( "This value is equal to length = x ft.<BR>\n" );
document.write( "So, 2y - 1 = x<BR>\n" );
document.write( "or 2y = x + 1 ________(1)\r<BR>\n" );
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document.write( "Perimeter = 2(Length + Width)<BR>\n" );
document.write( "So, 46 = 2(x + y) ________ (2)\r<BR>\n" );
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document.write( "Substituting, '2y' from (1) in (2)<BR>\n" );
document.write( "46 = 2x + (x + 1)<BR>\n" );
document.write( "or 3x = 46 - 1 = 45<BR>\n" );
document.write( "or x = 45/3<BR>\n" );
document.write( "or x = 15\r<BR>\n" );
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document.write( "So, y = (15 + 1)/2 = 8\r<BR>\n" );
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document.write( "Thus, length = 15 ft and width = 8 ft. </SPAN>\n" );
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