document.write( "Question 1059078: 10^(2x-1) + 4 = 20
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Algebra.Com's Answer #674176 by Alan3354(69443) $\"\"$ $\"About$

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10^(2x-1) + 4 = 20
\n" ); document.write( "10^(2x-1) = 16
\n" ); document.write( "2x-1 = log(16)
\n" ); document.write( "2x = log(16) + 1 = log(16) + log(10) = log(160)
\n" ); document.write( "x = log(160)/2
\n" ); document.write( "Or
\n" ); document.write( "x = log(sqrt(160))
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