document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1059065>Question 1059065</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of a rectangular field that has a perimeter of 724m  and an area of 32,400m^2  . </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #674157 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=674157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w be the width of the field, and l be the length. Then:<BR>\n" );
document.write( "P=2w+2l<BR>\n" );
document.write( "2w+2l=724<BR>\n" );
document.write( "w=362-1;<BR>\n" );
document.write( "w(362-w)=32400<BR>\n" );
document.write( "362w-w²=32400<BR>\n" );
document.write( "w²-362w+32400=0<BR>\n" );
document.write( "(w-200)(w-162)=0<BR>\n" );
document.write( "w=200 or 162<BR>\n" );
document.write( "The dimensions of your field are 200m by 162m. &#9786;&#9786;&#9786;&#9786;<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );