document.write( "Question 13366: Can you please help with this eqaution?\r
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document.write( "Here what I've tried so far.\r
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document.write( "2 [k-3(4-2k)] = 2(k-3) + 3
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document.write( "2[k-3-4+2k]=2k-6+3
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document.write( "2k-6-8+4k=2k-6+3
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document.write( "6k-14=2k-3
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document.write( "6k-6k-14=2k-6k-3
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document.write( "14+3=-4k-3-14
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document.write( "17=-4k
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Algebra.Com's Answer #6741 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Here what I've tried so far. \n" ); document.write( "2 [k-3(4-2k)] = 2(k-3) + 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your mistake is in the next step! You must multiply -3 times the 4 and times the -2k. \n" ); document.write( "2[k-3-4+2k]=2k-6+3 Error in this step!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It should be this: \n" ); document.write( "2[k-12 + 6k]= 2k - 6 + 3 \n" ); document.write( "2k - 24 + 12k = 2k - 3 \n" ); document.write( "14k - 24 = 2k - 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 2k from each side: \n" ); document.write( "14k - 2k - 24 = 2k - 2k - 3 \n" ); document.write( "12k - 24 = -3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 24 to each side: \n" ); document.write( "12k - 24 + 24 = -3 + 24 \n" ); document.write( "12k = 21\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " \n" ); document.write( " |