document.write( "Question 13366: Can you please help with this eqaution?\r
\n" ); document.write( "\n" ); document.write( "Here what I've tried so far.\r
\n" ); document.write( "\n" ); document.write( "2 [k-3(4-2k)] = 2(k-3) + 3
\n" ); document.write( "2[k-3-4+2k]=2k-6+3
\n" ); document.write( "2k-6-8+4k=2k-6+3
\n" ); document.write( "6k-14=2k-3
\n" ); document.write( "6k-6k-14=2k-6k-3
\n" ); document.write( "14+3=-4k-3-14
\n" ); document.write( "17=-4k
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Algebra.Com's Answer #6741 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Here what I've tried so far.
\n" ); document.write( "2 [k-3(4-2k)] = 2(k-3) + 3\r
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\n" ); document.write( "\n" ); document.write( "Your mistake is in the next step! You must multiply -3 times the 4 and times the -2k.
\n" ); document.write( "2[k-3-4+2k]=2k-6+3 Error in this step!\r
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\n" ); document.write( "\n" ); document.write( "It should be this:
\n" ); document.write( "2[k-12 + 6k]= 2k - 6 + 3
\n" ); document.write( "2k - 24 + 12k = 2k - 3
\n" ); document.write( "14k - 24 = 2k - 3\r
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\n" ); document.write( "\n" ); document.write( "Subtract 2k from each side:
\n" ); document.write( "14k - 2k - 24 = 2k - 2k - 3
\n" ); document.write( "12k - 24 = -3\r
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\n" ); document.write( "\n" ); document.write( "Add 24 to each side:
\n" ); document.write( "12k - 24 + 24 = -3 + 24
\n" ); document.write( "12k = 21\r
\n" ); document.write( "\n" ); document.write( "\"k+=+21%2F12+=+7%2F4+\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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