document.write( "Question 1058929: A farmer has 150 feet of fence available to enclose a 1125 square foot region in the shape of adjoining​ squares, with sides of length x and y. The big square has sides of length x and the small square has sides of length y. Find x and y \n" ); document.write( "
Algebra.Com's Answer #674075 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "A farmer has 150 feet of fence available to enclose a 1125 square foot region in the shape of adjoining​ squares,
\n" ); document.write( "with sides of length x and y. The big square has sides of length x and the small square has sides of length y. Find x and y
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document.write( "First equation is\r\n" );
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document.write( "\"x%5E2+%2B+y%5E2\" = 1125.             (1)    for the area.\r\n" );
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document.write( "The second equation is \r\n" );
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document.write( "4x + 4y - 2y = 150.         (2)    for the perimeter  (2y is distracted to account for the adjacent part of the two squares)\r\n" );
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document.write( "Simplifying (2), we have these two equations in the form\r\n" );
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document.write( "\"x%5E2+%2B+y%5E2\" = 1125,             (1)\r\n" );
document.write( "2x + y = 75.                (2)\r\n" );
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document.write( "From (2), express y = 75 - 2x and substitute it into (1) instead of y. You will get\r\n" );
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document.write( "\"x%5E2+%2B+%2875-2x%29%5E2\" = 1125.\r\n" );
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document.write( "Simplify:\r\n" );
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document.write( "\"5x%5E2+-+300y+%2B+5625\" = 1125,\r\n" );
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document.write( "\"5x%5E2+-+300y+%2B+4500\" = 0,\r\n" );
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document.write( "\"x%5E2+-+60x+%2B+900\" = 0.\r\n" );
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document.write( "\"%28x-30%29%5E2\" = 0.\r\n" );
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document.write( "x = 30 is the solution.\r\n" );
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document.write( "Answer.  x = 30 ft,  y = 75-2x = 75-2*30 = 15 ft.\r\n" );
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