document.write( "Question 1058965: Theresas five test grades for this semester are 86% 78% 68% 92% and 72% her final exam counts one third of her final grade what range of grades on her final exam results and Teresa receiving a final grade of B in the course for Teresa to obtain a B in this course her average messed be greater than or equal to 80 but less than 90. \r
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document.write( "86+78+68+92+72 = 396
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document.write( " 396÷5 = 79 .2
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document.write( " 1/3×79.2 equals 79.2÷3 equals 26.4 \r
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document.write( "I am unsure if I'm on the right track or what my next step would be. \n" );
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Algebra.Com's Answer #674063 by josgarithmetic(39626) ![]() You can put this solution on YOUR website! 86, 78, 68, 92, 72 are two-thirds of the course grade and some unknown T is worth one third of the course grade. Based on each normal test is 100 percentage points, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Reread a few times if needed until you understand that.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Theresa needs average 80 to 90 percent for grade of B. What should score T be?\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |