document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058956>Question 1058956</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Allowing 5% for waste, determine amount in feet of lead pipe 2 in. outer diameter, 1/4 in. thick from a ton of lead.  A cu. ft. of lead weighs 710 lbs. / cu. ft. \r<BR>\n" );
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document.write( "A pipe is considered a cylinder. \r<BR>\n" );
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document.write( ".95 * 2000 = 1900 lbs. (amt. of material). \r<BR>\n" );
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document.write( "Area of circle; pi ^ r*2 \r<BR>\n" );
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document.write( "Outer; 3.1416 * 1 * 1 = 3.1416 sq. in. <BR>\n" );
document.write( "Inner; 3.1416 * .75 * .75 = 1.76 sq. in. \r<BR>\n" );
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document.write( "3.1416 - 1.76 = 1.38 sq. in. (area of end). \r<BR>\n" );
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document.write( "3.1416 * .39 * .39 * h = .4778h \r<BR>\n" );
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document.write( "Unsure from here.  Thanks.\r<BR>\n" );
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document.write( "Non-homework.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #674036 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=674036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Allowing 5% for waste, determine amount in feet of lead pipe 2 in. outer diameter, 1/4 in. thick from a ton of lead.  A cu. ft. of lead weighs 710 lbs. / cu. ft. \r<BR>\n" );
document.write( "\n" );
document.write( "A pipe is considered a cylinder. \r<BR>\n" );
document.write( "\n" );
document.write( ".95 * 2000 = 1900 lbs. (amt. of material). \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Area of circle; pi ^ r*2 \r<BR>\n" );
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document.write( "Outer; 3.1416 * 1 * 1 = 3.1416 sq. in. <BR>\n" );
document.write( "Inner; 3.1416 * .75 * .75 = 1.76 sq. in. \r<BR>\n" );
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document.write( "3.1416 - 1.76 = 1.38 sq. in. (area of end). \r<BR>\n" );
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document.write( "3.1416 * .39 * .39 * h = .4778h <BR>\n" );
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document.write( "Cross-sectional area (CSA) = pi*(1^2 - 0.75^2) = 1.3745 sq inches<BR>\n" );
document.write( "Volume of pipe = CSA*length<BR>\n" );
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document.write( "2000 lbs/710 lb/cu ft = 2.8169 cu ft of Pb<BR>\n" );
document.write( "-5% = 0.95*2.8169 = 2.676 cu ft<BR>\n" );
document.write( "2.676*12*12*12 = 4624.225 cu inches<BR>\n" );
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document.write( "Vol of pipe = CSA*length<BR>\n" );
document.write( "L = 4624.225/1.3745 =~ 3364.3 inches<BR>\n" );
document.write( "=~ 280 feet<BR>\n" );
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