document.write( "Question 92593: Eight times the first of three consecutive odd integers is ten more than twice the second. \n" ); document.write( "

Algebra.Com's Answer #67403 by venugopalramana(3286) $\"\"$ $\"About$

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Eight times the first of three consecutive odd integers is ten more than twice the second.
\n" ); document.write( "ANY INTEGER IS N
\n" ); document.write( "EVEN NUMBER IS 2N
\n" ); document.write( "ODD INTEGER IS 2N+1
\n" ); document.write( "NEXT ODD INTEGER IS 2N+1+2=2N+3
\n" ); document.write( "THE NEXT ODD INTEGER IS 2N+3+2=2N+5
\n" ); document.write( "8 TIMES THE I = 8(2N+1)=16N+8
\n" ); document.write( "TWICE THE SECOND = 2(2N+3)=4N+6
\n" ); document.write( "TEN MORE =4N+6+10=4N+16.............HENCE
\n" ); document.write( "16N+8=4N+16
\n" ); document.write( "16N-4N=16-8
\n" ); document.write( "12N=8
\n" ); document.write( "N=8/12=......THERE IS NO SOLUTION.......PLEASE CHECK THE DATA IN THE PROBLEM
\n" ); document.write( "FOR ANY MISTAKES IN TYPING.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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