document.write( "Question 1058897: Solve cos(x/2)=-sinx on the interval 0 to 2pi \n" ); document.write( "
Algebra.Com's Answer #673989 by Alan3354(69443)\"\" \"About 
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Solve cos(x/2)=-sinx on the interval 0 to 2pi
\n" ); document.write( "--------
\n" ); document.write( "cos(x/2) = -2sin(x/2)*cos(x/2)
\n" ); document.write( "cos(x/2) + 2sin(x/2)*cos(x/2) = 0
\n" ); document.write( "cos(x/2)*(1 + 2sin(x/2)) = 0
\n" ); document.write( "---
\n" ); document.write( "cos(x/2) = 0
\n" ); document.write( "x/2 = pi/2, 3pi/2
\n" ); document.write( "--> x = pi
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\n" ); document.write( "1 + 2sin(x/2) = 0
\n" ); document.write( "2sin(x/2) = -1
\n" ); document.write( "sin(x/2) = -1/2
\n" ); document.write( "x/2 = 7pi/6, 11pi/6
\n" ); document.write( "--> x > 2pi\r
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