document.write( "Question 1058807: Use the factor theorem to prove that x^2 - x - 2 is a factor of x^3 - 6x^2 +3x + 10 \n" ); document.write( "
Algebra.Com's Answer #673905 by Boreal(15235)\"\" \"About 
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One can use synthetic division on each of the factors that make up x^2-x-2, (x-2)(x+1)
\n" ); document.write( "2/1===-6---3---10
\n" ); document.write( "--1===-4==-5==0
\n" ); document.write( "-1/1===-6==3==10
\n" ); document.write( "==1===-7==10==0
\n" ); document.write( "one can use long division, too.
\n" ); document.write( "========x-5
\n" ); document.write( "x^2-x-2/x^3-6x^2+3x+10
\n" ); document.write( "======x^3-x^2-2x
\n" ); document.write( "========-5x^2+5x+10
\n" ); document.write( "========-5x^2+5x+10
\n" ); document.write( "change signs and remainder is 0
\n" ); document.write( "The third factor is (x-5). \n" ); document.write( "
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