document.write( "Question 13372: 6-2x+3-(4x-1)=-2x+2 \n" ); document.write( "
Algebra.Com's Answer #6739 by elima(1433)\"\" \"About 
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6-2x+3-(4x-1)=-2x+2\r
\n" ); document.write( "\n" ); document.write( "First distribute the -1 outside the parenthesis to the (4x-1);\r
\n" ); document.write( "\n" ); document.write( "6-2x+3-4x+1=-2x+2
\n" ); document.write( "Now we add like terms;
\n" ); document.write( "6+3+1-2x-4x=-2x+2
\n" ); document.write( "10-6x=-2x+2
\n" ); document.write( "Subtract 2 from both sides:
\n" ); document.write( "10-6x-2=-2x+2-2
\n" ); document.write( "8-6x=-2x
\n" ); document.write( "Now add 6x to both sides;
\n" ); document.write( "8-6x+6x=-2x+6x
\n" ); document.write( "8=4x
\n" ); document.write( "divide both sides by 4;
\n" ); document.write( "\"8%2F4=4x%2F4\"
\n" ); document.write( "2=x
\n" ); document.write( "check;
\n" ); document.write( "6-2(2)+3-4(2)+1=-2(2)+2
\n" ); document.write( "6-4+3-8+1=-4+2
\n" ); document.write( "5-7=-2
\n" ); document.write( "-2=-2
\n" ); document.write( "Hope you understand
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