document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058789>Question 1058789</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help to Solve for x:   <BR>\n" );
document.write( " Log (x+3)+Log (x-2)=Log14\r<BR>\n" );
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document.write( "(all 3 Logs are to the base 10) \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673891 by </B><A HREF=/tutors/aboutme.mpl?userid=solve_for_x><B>solve_for_x(190)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solve_for_x><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using the logarithm law log(a) + log(b) = log(ab) gives:\r<BR>\n" );
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document.write( "log((x+3)(x-2)) = log(14)\r<BR>\n" );
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document.write( "Taking the antilog of both sides gives:\r<BR>\n" );
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document.write( "(x + 3)(x - 2) = 14\r<BR>\n" );
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document.write( "x^2 + x - 6 = 14\r<BR>\n" );
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document.write( "x^2 + x - 20 = 0\r<BR>\n" );
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document.write( "(x +5)(x - 4) = 0\r<BR>\n" );
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document.write( "x = -5, x = 4\r<BR>\n" );
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document.write( "Since the log function is not defined for values less than 0, the<BR>\n" );
document.write( "x = -5 solution is discarded because -5 + 3 = -2 and -5 - 2 = -7.\r<BR>\n" );
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document.write( "The only solution that works is x = 4.\r<BR>\n" );
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