document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058784>Question 1058784</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A labourer built 35m  of stone wall. If she had built 2m  less each day, it would have taken her 2 days longer. How many metres did she build each day, working at her usual rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673879 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673879\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> amount built per day is x m<BR>\n" );
document.write( "time it took was 35/x days<BR>\n" );
document.write( "if x-2 m, then it would have taken (35/x)+2 days longer<BR>\n" );
document.write( "Therefore, (35/x-2)=(35/x)+2<BR>\n" );
document.write( "Multiply everything by x (x-2)<BR>\n" );
document.write( "35x=35(x-2)+2x(x-2)<BR>\n" );
document.write( "35x=35x-70+2x^2-4x<BR>\n" );
document.write( "2x^2-4x-70=0<BR>\n" );
document.write( "x^2-2x-35=0, dividing by 2<BR>\n" );
document.write( "(x-7)(x+5)=0<BR>\n" );
document.write( "x=-5,7, use only 7 days<BR>\n" );
document.write( "That is 5 meters per day<BR>\n" );
document.write( "If she completed 5  meters per day, it would have taken 2 days longer, or 7 days.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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