document.write( "Question 1058775: I am looking for how I get the answer for:
\n" ); document.write( "ln(5x) = 3 + ln(x-1)\r
\n" ); document.write( "\n" ); document.write( "I move the natural logs to one side to make ln(5x) - ln(x-1) = 3, then use the properties of logarithms to get ln(5x/(x-1)) = 3. \r
\n" ); document.write( "\n" ); document.write( "I then make both sides a power of e to cancel out the ln and end up with 5x/(x-1) = e^3\r
\n" ); document.write( "\n" ); document.write( "I then multiply both sides by (x-1) to remove the fraction and get 5x = (e^3)x - e^3\r
\n" ); document.write( "\n" ); document.write( "Here is where I am stuck. I am unsure how to isolate the x. I know what the answer is supposed to be as this is a practice problem, but I don't know how to get there from here! And maybe I made a mistake in the process. Any help is greatly appreciated! Thank you!
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Algebra.Com's Answer #673869 by solve_for_x(190)\"\" \"About 
You can put this solution on YOUR website!
What you have is correct so far.\r
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\n" ); document.write( "\n" ); document.write( "From here:\r
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\n" ); document.write( "\n" ); document.write( "5x = (e^3)x - e^3\r
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\n" ); document.write( "\n" ); document.write( "rearrange the equation by adding e^3 to both sides, and subtracting
\n" ); document.write( "5x from both sides. This gives:\r
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\n" ); document.write( "\n" ); document.write( "(e^3)x - 5x = e^3\r
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\n" ); document.write( "\n" ); document.write( "Factor the left side to get:\r
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\n" ); document.write( "\n" ); document.write( "(e^3 - 5)x = e^3\r
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\n" ); document.write( "\n" ); document.write( "Finally, divide both sides by (e^3 - 5) to get:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+e%5E3+%2F+%28e%5E3+-+5%29\"\r
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\n" ); document.write( "\n" ); document.write( "If desired, this can be simplified as:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+1+-+%28e%5E3%2F5%29\"
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