document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058775>Question 1058775</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am looking for how I get the answer for:<BR>\n" );
document.write( "ln(5x) = 3 + ln(x-1)\r<BR>\n" );
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document.write( "I move the natural logs to one side to make ln(5x) - ln(x-1) = 3, then use the properties of logarithms to get ln(5x/(x-1)) = 3. \r<BR>\n" );
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document.write( "I then make both sides a power of e to cancel out the ln and end up with 5x/(x-1) = e^3\r<BR>\n" );
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document.write( "I then multiply both sides by (x-1) to remove the fraction and get 5x = (e^3)x - e^3\r<BR>\n" );
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document.write( "Here is where I am stuck. I am unsure how to isolate the x. I know what the answer is supposed to be as this is a practice problem, but I don't know how to get there from here! And maybe I made a mistake in the process. Any help is greatly appreciated! Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673868 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ln(5x/(x-1)) = 3<BR>\n" );
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document.write( "use definition of logarithm<BR>\n" );
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document.write( "5x/(x-1) = e^3<BR>\n" );
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document.write( "note that e = 2.71828<BR>\n" );
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document.write( "5x / (x-1) = (2.71828)^3 = 20.0855<BR>\n" );
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document.write( "5x = 20.0855 * (x-1)<BR>\n" );
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document.write( "5x = 20.0855x - 20.0855<BR>\n" );
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document.write( "15.0855x = 20.0855<BR>\n" );
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document.write( "x = 1.3314<BR>\n" );
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