document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058753>Question 1058753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that x and y are differentiable functions of t and <BR>\n" );
document.write( "y^2 = 2xy + 24. Find dx/dt given that x = 1, y = 6, and dy/dt = 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673850 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume that x and y are differentiable functions of t and <BR>\n" );
document.write( "y^2 = 2xy + 24. Find dx/dt given that x = 1, y = 6, and dy/dt = 2<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "y^2 = 2xy + 24<BR>\n" );
document.write( "y^2/2 = xy + 12<BR>\n" );
document.write( "y(dy/dt) = x*dy/dt + y*dx/dt<BR>\n" );
document.write( "6*2 = 1*2 + 6*dx/dt<BR>\n" );
document.write( "dx/dt = 5/3<BR>\n" );
document.write( " </SPAN>\n" );
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