document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058747>Question 1058747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me simplify this:\r<BR>\n" );
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document.write( "(cosx)/(1-tanx) + (sinx*cosx)/(sinx-cosx) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673843 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (cosx)/(1-tanx) + (sinx*cosx)/(sinx-cosx)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "(cosx)/(1-tanx) + sinx/(tanx - 1)<BR>\n" );
document.write( "- cosx/(tanx - 1) + sinx/(tanx - 1)<BR>\n" );
document.write( "= (sin - cos)/(1 - tan) = (sin - cos)/(1 - sin/cos)<BR>\n" );
document.write( "= (sin - cos)/((cos - sin)/cos)<BR>\n" );
document.write( "= 1/(1/cos)<BR>\n" );
document.write( "= cos(x)<BR>\n" );
document.write( " </SPAN>\n" );
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