document.write( "Question 1058745: After 40 pounds of water had been evaporated from a solution of salt and water that was 10% salt, the solution that resulted was 15% salt. Find the number of pounds in the original solution. \n" ); document.write( "

Algebra.Com's Answer #673840 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = pounds of original solution
\n" ); document.write( " $\"+.1x+\"$ = pounds of salt in original solution
\n" ); document.write( "-------------------------------------------
\n" ); document.write( "The amount of salt in solution does not change
\n" ); document.write( " $\"+.1x+%2F+%28+x+-+40+%29+=+.15+\"$
\n" ); document.write( " $\"+.1x+=+.15%2A%28+x++-+40+%29+\"$
\n" ); document.write( " $\"+.1x+=+.15x+-+6+\"$
\n" ); document.write( " $\"+.05x+=+6+\"$
\n" ); document.write( " $\"+x+=+120+\"$
\n" ); document.write( "------------------------------------
\n" ); document.write( "The original solution was 120 pounds
\n" ); document.write( "------------------------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+.1%2A120+=+12+\"$ pounds of salt
\n" ); document.write( "and
\n" ); document.write( " $\"+12+%2F+%28+120+-+40+%29+=+12%2F80+\"$
\n" ); document.write( " $\"+12%2F80+=+.15+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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