document.write( "Question 1058742: A bank robber, after completing his heist, jumps into his getaway car and
\n" ); document.write( "drives away from the scene of a crime, down a straight highway at 40 m/s. A police vehicle follows in pursuit, leaving the bank 2 minutes, after the
\n" ); document.write( "robber left. If the police travel at 42 m/s, how much time passes from when
\n" ); document.write( "the bank robber left the bank to when he was caught? \n" ); document.write( "
Algebra.Com's Answer #673831 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Since d = rt, after 2 minutes (120 seconds), the robber would be \r\n" );
document.write( "(42)(120) or 5040 meters ahead of the cop.  The cop's approach \r\n" );
document.write( "rate to the robber is then 42-40 or 2 m/s.  So since t = d/r, it \r\n" );
document.write( "would take the cops an additional 5040/2 = 2520 seconds to catch \r\n" );
document.write( "up.  So adding that to the 120 seconds, we get that 2640 seconds \r\n" );
document.write( "passed from when the robber left until the cop caught him.  And \r\n" );
document.write( "2640 seconds = 44 minutes.   \r\n" );
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document.write( "Edwin
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