document.write( "Question 1058717: A rectangular piece of land has been claimed using a 160 yard cord. If the length of this rectangular lot is 20 yards more than twice it's width, then what are the dimensions of the lot \n" ); document.write( "
Algebra.Com's Answer #673818 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "A rectangular piece of land has been claimed using a 160 yard cord. If the length of this rectangular lot
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document.write( "If \"w\" represents the width, then the length is 2w+20.\r\n" );
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document.write( "The perimeter is (2w+20) + w + (2w+20) + w = 6w + 40.\r\n" );
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document.write( "Hence, the equation is 6w + 40 = 160,  --->  6w = 120  --->  w = {{120/6}}} = 20.\r\n" );
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document.write( "Answer.  The width is 20 ft. The length is 2w + 20 = 2*20+20 = 60 ft.\r\n" );
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\n" ); document.write( "\n" ); document.write( "For many other similar solved problems see the lessons\r
\n" ); document.write( "\n" ); document.write( "    - Solved problems on the perimeter and side lengths of a triangle\r
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