document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058710>Question 1058710</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two solutions of salt water contain 0.09% and 0.29% salt respectively. A lab technician wants to make 1 liter of solution which contains 0.12% salt. How much of each solution should she use?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673797 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673797\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two solutions of salt water contain 0.09% and 0.29% salt respectively. A lab technician wants to make 1 liter of solution which contains 0.12% salt. How much of each solution should she use? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "salt + salt = salt<BR>\n" );
document.write( "0.09x + 0.29(1-x) = 0.12*1<BR>\n" );
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document.write( "9x + 29 - 29x = 12<BR>\n" );
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document.write( "-20x = -17<BR>\n" );
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document.write( "x = 0.85 liters (amt. of 9% solution needed)<BR>\n" );
document.write( "1-0.85 = 0.15 liters (amt. of 29% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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