document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058667>Question 1058667</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Log 2 = 0.301   log 3 = 0.477  log 5 = 0.699 using this information\r<BR>\n" );
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document.write( "    Find:-  a) Log 30   b)Log o.6  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673751 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Log 2 = 0.301 log 3 = 0.477 log 5 = 0.699 using this information<BR>\n" );
document.write( "Find:- a) Log 30 b)Log o.6 <BR>\n" );
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document.write( "a)<BR>\n" );
document.write( "We know: 2 * 3 * 5 = 30<BR>\n" );
document.write( "therefore: log(2) + log(3) + log(5) = log(30)<BR>\n" );
document.write( "then<BR>\n" );
document.write( "adding the logs: .301 + . 477 + .699 = 1.477 is log of 30<BR>\n" );
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document.write( "b)<BR>\n" );
document.write( "We know: 2 * 3 * .1 = .6 and we also know the log of .1 = -1<BR>\n" );
document.write( "therefore: log(2) + log(3) + log(.1) = log(.6)<BR>\n" );
document.write( "adding this: .301 + .477 - 1 = -.222 is the log of .1<BR>\n" );
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