document.write( "Question 1058647: A research concludes that the number of hours of exercise per week for adults is normally distributed with a mean of 3.5 hours and a standard deviation of 3 hours. Show all work. Just the answer, without supporting work, will receive no credit.
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document.write( "(a) Find the 80th percentile for the distribution of exercise time per week. (round the answer to 2 decimal places)
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document.write( "(b) What is the probability that a randomly selected adult has more than 7 hours of exercise per week? (round the answer to 4 decimal places) \n" );
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Algebra.Com's Answer #673737 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A research concludes that the number of hours of exercise per week for adults is normally distributed with a mean of 3.5 hours and a standard deviation of 3 hours. Show all work. Just the answer, without supporting work, will receive no credit. \n" ); document.write( "(a) Find the 80th percentile for the distribution of exercise time per week. (round the answer to 2 decimal places) \n" ); document.write( "sample mean:: 3.5 \n" ); document.write( "ME = 1.282*3 = 3.845 \n" ); document.write( "80% CI:: 3.5-3.845 < u < 3.5+3.845 \n" ); document.write( "80% CI: -0.345 < u < 7.345 \n" ); document.write( "----------------------------------------- \n" ); document.write( "(b) What is the probability that a randomly selected adult has more than 7 hours of exercise per week? (round the answer to 4 decimal places) \n" ); document.write( "z(7) = (7-3.5)/3 = 3.5/3 = 1.167 \n" ); document.write( "--- \n" ); document.write( "P(x > 7) = P(z > 1.167) = normalcdf(1.167,100) = 0.1217 \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " |