document.write( "Question 1058622: annette invested 8,400 in bank A at a certain interest rate per year and 7000 in bank B at an interest rate 1.5% higher. If the total income from the two investments is 751.80 at what interest rate was each amount invested? \n" ); document.write( "
Algebra.Com's Answer #673713 by solve_for_x(190)\"\" \"About 
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Let x represent the rate at Bank A.\r
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\n" ); document.write( "\n" ); document.write( "The rate at Bank B is then x + 1.5.\r
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\n" ); document.write( "\n" ); document.write( "The total interest earned is then:\r
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\n" ); document.write( "\n" ); document.write( "(8400)(x/100) + (7000)(x + 1.5)/100 = 751.80\r
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\n" ); document.write( "\n" ); document.write( "Multiplying through by 100 gives:\r
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\n" ); document.write( "\n" ); document.write( "8400x + 7000x + 10500 = 75180\r
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\n" ); document.write( "\n" ); document.write( "15400x + 10500 = 75180\r
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\n" ); document.write( "\n" ); document.write( "15400x = 75180 - 10500\r
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\n" ); document.write( "\n" ); document.write( "15400x = 64680\r
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\n" ); document.write( "\n" ); document.write( "x = 64680 / 15400\r
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\n" ); document.write( "\n" ); document.write( "x = 4.2\r
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\n" ); document.write( "\n" ); document.write( "Solution: The rate at Bank A is 4.2%, and the rate at Bank B is 4.2% + 1.5% = 5.7%\r
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\n" ); document.write( "\n" ); document.write( "8400(0.042) + 7000(0.057) = 352.80 + 399.00 = 751.80
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