document.write( "Question 1058619: find the point whose distance from (7,-3) is square root of 58 and whose abscissa equals its ordinate. Please show your solution. \n" ); document.write( "
Algebra.Com's Answer #673708 by solve_for_x(190)\"\" \"About 
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Since the abscissa and ordinate of the unknown point are the same, the point
\n" ); document.write( "can be represented by (x, x).\r
\n" ); document.write( "\n" ); document.write( "The distance from (7, -3) to (x, x) is given by:\r
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\n" ); document.write( "\n" ); document.write( "\"d%5E2+=+%287+-+x%29%5E2+%2B+%28x+%2B+3%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"d%5E2+=+49+-+14x+%2B+x%5E2+%2B+x%5E2+%2B+6x+%2B+9\"\r
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\n" ); document.write( "\n" ); document.write( "\"d%5E2+=+2x%5E2+-+8x+%2B+58\"\r
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\n" ); document.write( "\n" ); document.write( "Since the distance is equal to √58, we can write:\r
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\n" ); document.write( "\n" ); document.write( "\"%28sqrt%2858%29%29%5E2+=+2x%5E2+-+8x+%2B+58\"\r
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\n" ); document.write( "\n" ); document.write( "\"58+=+2x%5E2+-+8x+%2B+58\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2+-+8x+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%28x+-+4%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "This gives solutions of x = 0 and x = 4.\r
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\n" ); document.write( "\n" ); document.write( "Solution: There are two such points: (0, 0) and (4, 4)
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