document.write( "Question 1058611: Please help me with the following question.\r
\n" ); document.write( "\n" ); document.write( "Prove this identity:\r
\n" ); document.write( "\n" ); document.write( "(1-cos^2x)(1+cos^2x) = 2sin^2x - sin^4x
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Algebra.Com's Answer #673703 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
(1-cos^2x)(1+cos^2x) = 2sin^2x - sin^4x\r
\n" ); document.write( "\n" ); document.write( "\"%281-cos%5E2x%29%281%2Bcos%5E2x%29+=+2sin%5E2x+-+sin%5E4x\"\r
\n" ); document.write( "\n" ); document.write( "\"%281-cos%5E2%28x%29%29%281%2Bcos%5E2%28x%29%29+=+2sin%5E2%28x%29+-+sin%5E4%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "RHS,
\n" ); document.write( "\"sin%5E2%28x%29%282-sin%5E2%28x%29%29\"
\n" ); document.write( "\"%281-cos%5E2%28x%29%29%282-sin%5E2%28x%29%29\"
\n" ); document.write( "\"%281-cos%5E2%28x%29%29%282-%281-cos%5E2%28x%29%29%29\"
\n" ); document.write( "\"%281-cos%5E2%28x%29%29%282-1%2Bcos%5E2%28x%29%29\"
\n" ); document.write( "\"%281-cos%5E2%28x%29%29%281%2Bcos%5E2%28x%29%29\"------------Identical to LHS
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