document.write( "Question 13369: find three consecutive intergers that eual out to be 45....\r
\n" ); document.write( "\n" ); document.write( "when i did it my teacher counted it wrong...my answer was 14, 15, 16...i guess she wants me to show her how i got it??? can you help me with this?
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Algebra.Com's Answer #6737 by elima(1433)\"\" \"About 
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find three consecutive intergers that equal out to be 45....\r
\n" ); document.write( "\n" ); document.write( "Let x be the first integer; so we have
\n" ); document.write( "x; then the second integer would be x+1; then the third would br x+2;\r
\n" ); document.write( "\n" ); document.write( "x+(x+1)+(x+2)=45
\n" ); document.write( "We add all the x's and the ones together:
\n" ); document.write( "3x+3=45
\n" ); document.write( "We subtract 3 from both sides;
\n" ); document.write( "3x+3-3=45-3
\n" ); document.write( "3x=42
\n" ); document.write( "Divide 3 from both sides;
\n" ); document.write( "\"3x%2F3=45%2F3\"
\n" ); document.write( "x=14
\n" ); document.write( "So the first integer would be 14; then the second 14+1=15; and the third 14+2=16\r
\n" ); document.write( "\n" ); document.write( "So we have 14+15+16=45\r
\n" ); document.write( "\n" ); document.write( "=) \n" ); document.write( "
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