document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058198>Question 1058198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that in a key punching of 80 column IBM cards, the arithmetic mean number of mistakes per card is 0.3. What percent of cards will have (i) no mistake, (ii) one mistake (iii) two mistakes? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673698 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> random, proportional to number, could be infinite, discrete<BR>\n" );
document.write( "Poisson distribution with parameter 0.3<BR>\n" );
document.write( "e^(-lambda)*lambda^x/x!<BR>\n" );
document.write( "For 0, it is e^(-0.3)=0.7408<BR>\n" );
document.write( "for 1 it is 0.7408(0.3)=0.2222<BR>\n" );
document.write( "for 2 it is 0.7408*(0.3^2)/2=0.0334 </SPAN>\n" );
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