document.write( "Question 1058528: 2cos(2x)^2 - cosx + 2sin2x = 1 where x is between [-π/2 , 3π/2] \n" ); document.write( "
Algebra.Com's Answer #673691 by Alan3354(69443)\"\" \"About 
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2cos(2x)^2
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\n" ); document.write( "Is that 2cos(4x^2) ?
\n" ); document.write( "Or 2cos^2(2x) ?
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