document.write( "Question 1058528: 2cos(2x)^2 - cosx + 2sin2x = 1 where x is between [-π/2 , 3π/2] \n" ); document.write( "
Algebra.Com's Answer #673691 by Alan3354(69443)    You can put this solution on YOUR website! 2cos(2x)^2 \n" ); document.write( "---- \n" ); document.write( "Is that 2cos(4x^2) ? \n" ); document.write( "Or 2cos^2(2x) ? \n" ); document.write( "  |