document.write( "Question 1058595: The owner of Britten’s Egg Farm wants to estimate the mean number of eggs produced per chicken. A sample of 19 chickens shows they produced an average of 18 eggs per month with a standard deviation of 4 eggs per month. (Use t Distribution Table.)
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document.write( "a. What is the value of the population mean?
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document.write( " a.) 4
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document.write( " b.) It is unknown.
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document.write( " c.) 18
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document.write( "b. What is the best estimate of this value?
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document.write( " Best estimate:
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document.write( "c.
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document.write( "For a 98% confidence interval, what is the value of t? (Round your answer to 3 decimal places.)
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document.write( " Value of t:
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document.write( "d.
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document.write( "Develop the 98% confidence interval for the population mean. (Round your answers to 2 decimal places.)
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document.write( " Confidence interval from to .
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document.write( "e-1. Would it be reasonable to conclude that the population mean is 19 eggs?
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document.write( " a.) No
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document.write( " b.) Yes
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document.write( "e-2. What about 24 eggs?
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document.write( " a.) No
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document.write( " b.) Yes
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Algebra.Com's Answer #673676 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! a. The answer is b, \n" ); document.write( "The best estimate is the sample mean of 18 eggs/mo. \n" ); document.write( "98% CI interval width is t(df=18,0.99)s/sqrt(n); t=2.552. \n" ); document.write( "That is 2.552*4/sqrt(19)=2.342 \n" ); document.write( "(15.66, 20.34) \n" ); document.write( "Yes, it would be reasonable, because 19 is in the interval. \n" ); document.write( "No, because 24 is not in the interval.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |