document.write( "Question 92516: Hello out there,I need some help with some problems,The first one is,Find the y-intercept of y=2^x.The next one is,Use quadratic formula to solve:5x^2+12=-6x.The third one is,Use the quadratic formula to solve:x^2+12x+11=0.The last one is,Describe how the graph of y=(x-6)^2+5 changes from the parent graph of y=x^2.Thanks for any one can help. \n" ); document.write( "
Algebra.Com's Answer #67365 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1.Find the y-intercept of y=2^x. \n" ); document.write( "The y intercept occurs when x = 0, we know that any number to the power of 0 is equal to 1. \n" ); document.write( "y = 2^0 \n" ); document.write( "y = 1 \n" ); document.write( ": \n" ); document.write( "2. Use quadratic formula to solve:5x^2+12=-6x. Put into the ax^2 + bx + c = 0 format. \n" ); document.write( "5x^2 + 12 = -6x \n" ); document.write( "5x^2 + 6x + 12 = 0 \n" ); document.write( ": \n" ); document.write( "a = 5; b = 6; c = 12 \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "You can see that the discriminant will be < 0, no real roots \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "3. Use the quadratic formula to solve:x^2+12x+11=0. \n" ); document.write( "a = 1; b = 12; c = 11 \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Two solutions: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x = -1 \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x = -11 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "4.Describe how the graph of y=(x-6)^2+5 changes from the parent graph of y=x^2. \n" ); document.write( "Minimum is at origin in y = x^2, minimum is at x/y coordinate 6,5 for y = (x-6)^2 + 5 \n" ); document.write( ": \n" ); document.write( " |