document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058551>Question 1058551</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An angle is 1/5 of its supplement . what is its magnitude </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673625 by </B><A HREF=/tutors/aboutme.mpl?userid=solve_for_x><B>solve_for_x(190)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solve_for_x><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673625\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x represent the unknown angle.\r<BR>\n" );
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document.write( "It supplement will be 180 - x.\r<BR>\n" );
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document.write( "Since the unknown angle is 1/5 of its supplement, you can write:\r<BR>\n" );
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document.write( "x = (1/5)(180 - x)\r<BR>\n" );
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document.write( "Multiplying both sides by 5 then gives:\r<BR>\n" );
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document.write( "5x = 180 - x\r<BR>\n" );
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document.write( "Adding x to both sides gives:\r<BR>\n" );
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document.write( "6x = 180\r<BR>\n" );
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document.write( "Dividing both sides by 6 leaves:\r<BR>\n" );
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document.write( "x = 180 / 6\r<BR>\n" );
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document.write( "x = 30\r<BR>\n" );
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document.write( "Solution: The magnitude of the angle is 30. </SPAN>\n" );
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