document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058544>Question 1058544</A>: <I><SPAN STYLE=\"word-break: break-all;\"> on two investments totaling $6000, kevin lost 3% on one and earned 6% on the other. if his net annual receipts were $288, how much was each investment? answer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673607 by </B><A HREF=/tutors/aboutme.mpl?userid=solve_for_x><B>solve_for_x(190)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solve_for_x><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x represent the amount invested in the investment that lost value, <BR>\n" );
document.write( "and let y represent the amount invested in the investment that gained<BR>\n" );
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document.write( "Since the total investment was $6000, you can write:\r<BR>\n" );
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document.write( "x + y = 6000\r<BR>\n" );
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document.write( "The total amount gained is then\r<BR>\n" );
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document.write( "-0.03x + 0.06y = 288\r<BR>\n" );
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document.write( "Solving the first equation for y gives:\r<BR>\n" );
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document.write( "y = 6000 - x\r<BR>\n" );
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document.write( "Substituting 6000 - x in place of y in the second equation then gives:\r<BR>\n" );
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document.write( "-0.03x + 0.06(6000 - x) = 288\r<BR>\n" );
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document.write( "-0.03x + 360 - 0.06x = 288\r<BR>\n" );
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document.write( "-0.09x + 360 = 288\r<BR>\n" );
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document.write( "-0.09x = -72\r<BR>\n" );
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document.write( "x = -72 / -0.09\r<BR>\n" );
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document.write( "x = 800\r<BR>\n" );
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document.write( "Then y = 6000 - 800 = 5200\r<BR>\n" );
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document.write( "Solution: $800 was invested in the account the lost value, and $5200 was invested<BR>\n" );
document.write( "in the account that gained value.\r<BR>\n" );
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document.write( "Check:\r<BR>\n" );
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document.write( "x + y = 800 + 5200 = 6000\r<BR>\n" );
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document.write( "-0.03x + 0.06y = (-0.03)(800) + (0.06)(5200) = -24 + 312 = 288 </SPAN>\n" );
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