document.write( "Question 1058413: Total profit P is the difference between total revenue R and total cost C. Given the following total-revenue and total-cost functions, find the total profit, the maximum value of the total profit, and the value of x at which it occurs.\r
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document.write( "R(x)= 1000x-(x squared)\r
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document.write( "C(x)= 3400+10x \n" );
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Algebra.Com's Answer #673583 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Total profit P is the difference between total revenue R and total cost C. \n" ); document.write( " Given the following total-revenue and total-cost functions, find the total profit, the maximum value of the total profit, and the value of x at which it occurs. \n" ); document.write( "R(x)= 1000x-x^2 \n" ); document.write( "C(x)= 3400+10x \n" ); document.write( ": \n" ); document.write( "Profit = Revenue - Cost \n" ); document.write( "P(x) = (1000x - x^2) - (3400+ 10x) \n" ); document.write( "remove brackets \n" ); document.write( "P(x) = 1000x - x^2 - 3400 - 10x \n" ); document.write( "combine like terms \n" ); document.write( "P(x) = -x^2 + 1000x - 10x - 3400 \n" ); document.write( "A quadratic equation \n" ); document.write( "P(x) = -x^2 + 990x - 3400 \n" ); document.write( "Max profit occurs on the axis of symmetry, x = -b/(2a) \n" ); document.write( "x = \n" ); document.write( "x = 495 units will produce max profit \n" ); document.write( "Find that actual profit \n" ); document.write( "P(x) = -(495^2) + 990(495) - 3400 \n" ); document.write( "P(x) = -245025 + 490050 - 3400 \n" ); document.write( "P(x) = $241,625 value of the total profit\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |