document.write( "Question 1058474: Jack is 4 times as old as lacy. 5 years from now the sum of their ages will be 85. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #673551 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Jack is 4 times as old as Lacy. \n" ); document.write( "J = 4L..........Eq(1) \n" ); document.write( "5 years from now the sum of their ages will be 85 \n" ); document.write( "J + 5 + L + 5 = 85........Eq(2) \n" ); document.write( "Replace J in Eq(2) with 4L from Eq(1). \n" ); document.write( "4L + 5 + L + 5 = 85 \n" ); document.write( "Collect like terms \n" ); document.write( "4L + L = 85 - 5 - 5 \n" ); document.write( "5L = 75 \n" ); document.write( "L = 25 \n" ); document.write( "Ages currently are: \n" ); document.write( "Jack = 60 years old \n" ); document.write( "Lacy = 15 years old. \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |