document.write( "Question 1058474: Jack is 4 times as old as lacy. 5 years from now the sum of their ages will be 85. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #673551 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "Jack is 4 times as old as Lacy.
\n" ); document.write( "J = 4L..........Eq(1)
\n" ); document.write( "5 years from now the sum of their ages will be 85
\n" ); document.write( "J + 5 + L + 5 = 85........Eq(2)
\n" ); document.write( "Replace J in Eq(2) with 4L from Eq(1).
\n" ); document.write( "4L + 5 + L + 5 = 85
\n" ); document.write( "Collect like terms
\n" ); document.write( "4L + L = 85 - 5 - 5
\n" ); document.write( "5L = 75
\n" ); document.write( "L = 25
\n" ); document.write( "Ages currently are:
\n" ); document.write( "Jack = 60 years old
\n" ); document.write( "Lacy = 15 years old.
\n" ); document.write( "Hope this helps :-)
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