document.write( "Question 1058477: Katie has a collection of nickels, dimes, and quarters with a total value of $4.65. There are 5 more dimes than nickels and 7 more quarters than nickels, how many of each coin does she have?
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Algebra.Com's Answer #673543 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let \n" ); document.write( " n = number of nickels \n" ); document.write( " d = number of dimes \n" ); document.write( " q = number of quarters\r \n" ); document.write( "\n" ); document.write( "….\r \n" ); document.write( "\n" ); document.write( "5n + 10d + 25q = 465 (total value, in cents) \n" ); document.write( "d = n + 5 (5 more dimes than nickels) \n" ); document.write( "q = n + 7 (7 more quarters than nickels)\r \n" ); document.write( "\n" ); document.write( "The easiest thing to do at this point is to substitute for d & q in the top equation.\r \n" ); document.write( "\n" ); document.write( "5n + 10(n+5) + 25(n+7) = 465\r \n" ); document.write( "\n" ); document.write( "Can you solve for n?\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |