document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92521>Question 92521</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ok, I answered this but I want to make sure that I got it right before turning it in.\r<BR>\n" );
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document.write( "Solve the system by addition or substitution.<BR>\n" );
document.write( "     3x – 4y = 8<BR>\n" );
document.write( "     6x – 2y = 10<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67353 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67353\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiply the first equation by -2 & add:<BR>\n" );
document.write( "-6x+8y=-16<BR>\n" );
document.write( "6x-2y=10<BR>\n" );
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document.write( "6y=-6<BR>\n" );
document.write( "y=-6/6<BR>\n" );
document.write( "y=-1 answer.<BR>\n" );
document.write( "6x-2*-1=10<BR>\n" );
document.write( "6x+2=10<BR>\n" );
document.write( "6x=10-2<BR>\n" );
document.write( "6x=8<BR>\n" );
document.write( "x=8/6<BR>\n" );
document.write( "x=4/3 answer. </SPAN>\n" );
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