document.write( "Question 1058324: Prove
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Algebra.Com's Answer #673494 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"%28tan%28A%2BB%29-tan%28A%29%29%2F%281%2Btan%28A%2BB%29tan+A%29\"\"%22%22=%22%22\"\"tan%28B%29\"\r\n" );
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document.write( "We work with the left side\r\n" );
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document.write( "The formula for \"tan%28alpha-beta%29\" is\r\n" );
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document.write( "\"tan%28alpha-beta%29\"\"%22%22=%22%22\"\"%28tan%28alpha%29-tan%28beta%29%29%2F%281%2Btan%28alpha%29tan%28beta%29%29\"\r\n" );
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document.write( "If we substitute \"alpha=A%2BB\" and \"beta=A\"\r\n" );
document.write( "in that formula\r\n" );
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document.write( "\"tan%28%28A%2BB%29-A%29\"\"%22%22=%22%22\"\"%28tan%28A%2BB%29-tan%28A%29%29%2F%281%2Btan%28A%2BB%29tan%28A%29%29\"\r\n" );
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document.write( "the right side is the the same as the left side of\r\n" );
document.write( "the identity we are to prove, so the left side is\r\n" );
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document.write( "\"tan%28%28A%2BB%29-A%29\"\r\n" );
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document.write( "which becomes\r\n" );
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document.write( "\"tan%28A%2BB-A%29\"\r\n" );
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document.write( "\"tan%28B%29\"\r\n" );
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document.write( "Edwin
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