document.write( "Question 1058407: Find the area of the triangle formed by the x- and y- axes and the line 12x + 10y = 30. \n" ); document.write( "
Algebra.Com's Answer #673454 by solve_for_x(190)\"\" \"About 
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The x- and y- axes and the line 12x + 10y = 30 form a right triangle with the 90 degree angle at the origin.\r
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\n" ); document.write( "\n" ); document.write( "To determine the base and height of the triangle, find the x- and y-intercepts of the given line.\r
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\n" ); document.write( "\n" ); document.write( "To find the x-intercept, set y = 0 and solve for x:\r
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\n" ); document.write( "\n" ); document.write( "12x + 10(0) = 30\r
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\n" ); document.write( "\n" ); document.write( "12x = 30\r
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\n" ); document.write( "\n" ); document.write( "x = 30/12\r
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\n" ); document.write( "\n" ); document.write( "x = 2.5\r
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\n" ); document.write( "\n" ); document.write( "To find the y-intercept, set x = 0 and solve for y:\r
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\n" ); document.write( "\n" ); document.write( "12(0) + 10y = 30\r
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\n" ); document.write( "\n" ); document.write( "10y = 30\r
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\n" ); document.write( "\n" ); document.write( "y = 3\r
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\n" ); document.write( "\n" ); document.write( "The base of triangle is 2.5, and the height is 3.\r
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\n" ); document.write( "\n" ); document.write( "The area is then:\r
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\n" ); document.write( "\n" ); document.write( "Area = (1/2)(base)(height) = (1/2)(2.5)(3) = 3.75
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