document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058386>Question 1058386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is six less than a second number. Six times the first is 3 more than 3 times the second. Find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673453 by </B><A HREF=/tutors/aboutme.mpl?userid=solve_for_x><B>solve_for_x(190)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solve_for_x><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x represent the first number, and x + 6 represent the second number.\r<BR>\n" );
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document.write( "Then \"six times the first is 3 more than 3 times the second\" can be written as the <BR>\n" );
document.write( "following equation:\r<BR>\n" );
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document.write( "6x = 3(x + 6) + 3\r<BR>\n" );
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document.write( "Expanding the terms on the right side gives:\r<BR>\n" );
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document.write( "6x = 3x + 18 + 3\r<BR>\n" );
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document.write( "6x = 3x + 21\r<BR>\n" );
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document.write( "6x - 3x = 21\r<BR>\n" );
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document.write( "3x = 21\r<BR>\n" );
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document.write( "x = 7\r<BR>\n" );
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document.write( "The first number is 7.\r<BR>\n" );
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document.write( "The second number is x + 6 = 7 + 6 = 13. </SPAN>\n" );
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