document.write( "Question 1058395: The ratio of length to width in a rectangle is 3 to 1. If the perimeter of the rectangle is 152 feet, what is the length of the rectangle?
\n" ); document.write( "Select one:
\n" ); document.write( "a. 57 feet
\n" ); document.write( "b. 76 feet
\n" ); document.write( "c. 114 feet
\n" ); document.write( "d. 38 feet
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Algebra.Com's Answer #673447 by jim_thompson5910(35256)\"\" \"About 
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\"The ratio of length to width in a rectangle is 3 to 1\" means \"L%2FW=3%2F1\" leading to \"L+=+3W\" after we solve for L\r
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\n" ); document.write( "\n" ); document.write( "In other words, the length is three times longer than the width. \r
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\n" ); document.write( "\n" ); document.write( "\" the perimeter of the rectangle is 152 feet\" so P = 152\r
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\n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle: \r
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\n" ); document.write( "\n" ); document.write( "\"P+=+2%2AL%2B2%2AW\"\r
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\n" ); document.write( "\n" ); document.write( "\"P+=+2%2A3W%2B2%2AW\" Replace L with 3W. This works because we found earlier that \"L+=+3W\"\r
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\n" ); document.write( "\n" ); document.write( "\"152+=+2%2A3W%2B2%2AW\" Replace P with 152; now we solve for W\r
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\n" ); document.write( "\n" ); document.write( "\"152+=+6W%2B2W\"\r
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\n" ); document.write( "\n" ); document.write( "\"152+=+8W\"\r
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\n" ); document.write( "\n" ); document.write( "\"8W+=+152\"\r
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\n" ); document.write( "\n" ); document.write( "\"8W%2F8+=+152%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+19\"\r
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\n" ); document.write( "\n" ); document.write( "The width is 19 feet\r
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\n" ); document.write( "\n" ); document.write( "Use this to find the length\r
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\n" ); document.write( "\n" ); document.write( "\"L+=+3W\"\r
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\n" ); document.write( "\n" ); document.write( "\"L+=+3%2A19\" Replace W with 19\r
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\n" ); document.write( "\n" ); document.write( "\"L+=+57\"\r
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\n" ); document.write( "\n" ); document.write( "and the length is 57 feet\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the final answer is choice A) 57 feet
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