document.write( "Question 1058394: Show that the sum of three consecutive integers is always equal to 3 times the middle integer
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #673444 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "smallest integer = n\r\n" );
document.write( "middle integer = n+1\r\n" );
document.write( "largest integer = n+2\r\n" );
document.write( "\r\n" );
document.write( "Their sum = n+(n+1)+(n+2) = n+n+1+n+2 = 3n+3 = 3(n+1)\r\n" );
document.write( "\r\n" );
document.write( "3(n+1) is 3 times n+1, which is the middle integer.\r\n" );
document.write( "\r\n" );
document.write( "So we have proved it.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );