document.write( "Question 1058329: Question
\n" ); document.write( "During rush periods, accidents happen in Nicosia at a rate of 2 per hour. The morning rush period lasts for 1 hour 30 minutes, and the evening rush period for two hours.
\n" ); document.write( "1. What is the probability that there will be no accidents during the morning rush period?
\n" ); document.write( "2. What is the probability of 2 accidents during the evening?
\n" ); document.write( "3. What is the probability of four or more accidents during the morning?
\n" ); document.write( "4. What is the probability that there will be no accidents during both the morning and evening rush period?
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Algebra.Com's Answer #673375 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
We use the Poisson probability(P) distribution
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\n" ); document.write( "Probability ( x, u ) = (e^(-u) * u^x) / x!, where u is average number of successes, x is actual successes, e is approx 2.71828
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\n" ); document.write( "1) P ( x = 0 ) = (e^-3) * 3^0) / 0! = 0.0498
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\n" ); document.write( "2) P ( x = 2 ) = (e^-4) * 4^2) / 2! = 0.1465
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\n" ); document.write( "3) P ( x > or = 4 ) = 1 - summation i = 0, 3 of P (x = i ) with u = 3
\n" ); document.write( "P ( x = 0 ) = 0.0498
\n" ); document.write( "P ( x = 1 ) = 0.1494
\n" ); document.write( "P ( x = 2 ) = 0.2240
\n" ); document.write( "P ( x = 3 ) = 0.2240
\n" ); document.write( "P ( x > or = 4 ) = 1 - 0.6472 = 0.3528
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\n" ); document.write( "4) P ( x = 0 ) where u = 7 is 0.0009
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