document.write( "Question 1058327: Find the dimensions of a rectangle whose width is 6 miles less than its length and whose area is 55 square miles \n" ); document.write( "
Algebra.Com's Answer #673366 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make the length = x \n" ); document.write( "Width = x - 6 \n" ); document.write( "Area = length x width \n" ); document.write( "55 = x(x - 6) \n" ); document.write( "Rearrange \n" ); document.write( "x^2 - 6x = 55 \n" ); document.write( "x^2 - 6x - 55 = 0 \n" ); document.write( "Factorize \n" ); document.write( "(x - 11)(x + 5) = 0 \n" ); document.write( "x + 5 = 0 \n" ); document.write( "x = -5 disregard as -ve \n" ); document.write( "x - 11 = 0 \n" ); document.write( "x = 11 \n" ); document.write( "Length = 11 miles \n" ); document.write( "Width = 5 miles \n" ); document.write( "Area = 11 x 5 \n" ); document.write( "Area = 55 miles^2 \n" ); document.write( "Hope this helps :-) \n" ); document.write( " \n" ); document.write( " |