document.write( "Question 1058327: Find the dimensions of a rectangle whose width is 6 miles less than its length and whose area is 55 square miles \n" ); document.write( "
Algebra.Com's Answer #673366 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "Make the length = x
\n" ); document.write( "Width = x - 6
\n" ); document.write( "Area = length x width
\n" ); document.write( "55 = x(x - 6)
\n" ); document.write( "Rearrange
\n" ); document.write( "x^2 - 6x = 55
\n" ); document.write( "x^2 - 6x - 55 = 0
\n" ); document.write( "Factorize
\n" ); document.write( "(x - 11)(x + 5) = 0
\n" ); document.write( "x + 5 = 0
\n" ); document.write( "x = -5 disregard as -ve
\n" ); document.write( "x - 11 = 0
\n" ); document.write( "x = 11
\n" ); document.write( "Length = 11 miles
\n" ); document.write( "Width = 5 miles
\n" ); document.write( "Area = 11 x 5
\n" ); document.write( "Area = 55 miles^2
\n" ); document.write( "Hope this helps :-)
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