document.write( "Question 1058294: a) In 2006 a new Ford Focus costs $15,574. The value of a focus decreases exponentially over time. Write a Formula for the value of a Focus that was new in 2006. (You don't know the value of the decay factor yet). \r
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document.write( "So would I use this formula: \r
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document.write( "P(2006)= 15,574(1-b)^1\r
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document.write( "b) A 2 year old Focus costs $11,788. Find the decay factor and percent rate of depreciation.\r
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document.write( "c)How much would a 4 year old Focus cost? \n" );
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Algebra.Com's Answer #673331 by josgarithmetic(39623)![]() ![]() ![]() You can put this solution on YOUR website! b will contain the decay factor if you are using that formula shown. You have two points, (t,P). Try re-handling the variable so you have t=0 for year 2006 and t=2 for year 2008. Your two points are (0,15574) and (2,11788).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You choose the base you want, but \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Look at the second point: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can break the b into its percents pieces as \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The four-year value would be the evaluation |