document.write( "Question 1058294: a) In 2006 a new Ford Focus costs $15,574. The value of a focus decreases exponentially over time. Write a Formula for the value of a Focus that was new in 2006. (You don't know the value of the decay factor yet). \r
\n" ); document.write( "\n" ); document.write( "So would I use this formula: \"P%28t%29=P%5Bo%5Db%5Et\"\r
\n" ); document.write( "\n" ); document.write( "P(2006)= 15,574(1-b)^1\r
\n" ); document.write( "\n" ); document.write( "b) A 2 year old Focus costs $11,788. Find the decay factor and percent rate of depreciation.\r
\n" ); document.write( "\n" ); document.write( "c)How much would a 4 year old Focus cost?
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Algebra.Com's Answer #673331 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
b will contain the decay factor if you are using that formula shown. You have two points, (t,P). Try re-handling the variable so you have t=0 for year 2006 and t=2 for year 2008. Your two points are (0,15574) and (2,11788).\r
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\n" ); document.write( "\n" ); document.write( "You choose the base you want, but \"log%28%28P%29%29=log%28%28P%5Bo%5D%29%29%2Blog%28%28b%5Et%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%28P%29%29=t%2Alog%28%28b%29%29%2Blog%28%28P%5Bo%5D%29%29\", but not sure if this is necessary.\r
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\n" ); document.write( "\n" ); document.write( "Look at the second point:
\n" ); document.write( "\"11788=15574%2Ab%5E2\"
\n" ); document.write( "\"b%5E2=11788%2F15574\"
\n" ); document.write( "\"b%5E2=0.7569026\"
\n" ); document.write( "\"highlight%28b=0.87%29\" for model as \"highlight%28P%28t%29=15574%280.87%29%5Et%29\".\r
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\n" ); document.write( "\n" ); document.write( "You can break the b into its percents pieces as \"1.00-0.13\". This is a yearly decrease of 13%.\r
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\n" ); document.write( "\n" ); document.write( "The four-year value would be the evaluation \"P%284%29=15574%2A%280.87%29%5E4\".
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