document.write( "Question 1056260: The length of a rectangle is 13 centimeters less than four times its width. Its area is 35 square centimeters. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #673318 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "The length of a rectangle is 13 centimeters less than four times its width. Its area is 35 square centimeters. Find the dimensions of the rectangle.
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Let width be W
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document.write( "Then length = 4W - 13
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document.write( "We then get the following AREA equation: W(4W - 13) = 35
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document.write( "\"4W%5E2+-+13W+=+35\"
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document.write( "\"4W%5E2+-+13W+-+35+=+0\"
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document.write( "(W - 5)(4W + 7) = 0----- Factoring the TRINOMIAL
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document.write( "W, or width = \"highlight_green%28matrix%281%2C2%2C+5%2C+cm%29%29\"         OR        \"W+=+%28-+7%29%2F4\" (ignore)
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document.write( "Length: \"highlight_green%28matrix%281%2C4%2C+35%2F5%2C+or%2C+7%2C+cm%29%29\" \n" );
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