document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058272>Question 1058272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jessie has dimes and nickels in his piggy bank. The number of nickels is 3 times the number of dimes. If the total amount is $8.50, how many coins are there in total  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673313 by </B><A HREF=/tutors/aboutme.mpl?userid=solve_for_x><B>solve_for_x(190)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solve_for_x><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n represent the number of nickels, and let d represent the number of dimes.\r<BR>\n" );
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document.write( "Since the number of nickels is 3 times the number of dimes, you can write:\r<BR>\n" );
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document.write( "n = 3d\r<BR>\n" );
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document.write( "The total value of the coins is:\r<BR>\n" );
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document.write( "0.05n + 0.10d = 8.50\r<BR>\n" );
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document.write( "Substituting 3d in place of n gives:\r<BR>\n" );
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document.write( "0.05(3d) + 0.10d = 8.50\r<BR>\n" );
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document.write( "0.15d + 0.10d = 8.50\r<BR>\n" );
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document.write( "0.25d = 8.50\r<BR>\n" );
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document.write( "d = 8.50 / 0.25\r<BR>\n" );
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document.write( "d = 34\r<BR>\n" );
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document.write( "The number of dimes is 34.\r<BR>\n" );
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document.write( "The number of nickels is then 3 * 34 = 102.\r<BR>\n" );
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document.write( "Check:\r<BR>\n" );
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document.write( "0.05(102) + 0.10(34) = 5.10 + 3.40 = 8.50\r<BR>\n" );
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document.write( "Solution: He has 34 dimes and 102 nickels. </SPAN>\n" );
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