document.write( "Question 1058256: The digits 2, 3, 4, 5, 6, and 7 are randomly arranged to form a​ three-digit number. ​ (Digits are not​ repeated.) Find the probability that the number is even and greater than 700. \n" ); document.write( "
Algebra.Com's Answer #673299 by solve_for_x(190)\"\" \"About 
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Since the number must be greater than 700, there is only one choice for the first digit: 7\r
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\n" ); document.write( "\n" ); document.write( "Since the number must be even, there are only 3 choices for the last digit: 2, 4, 6\r
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\n" ); document.write( "\n" ); document.write( "And since there are no repeated digits, there are only 4 choices for the middle digit (cannot be 7, or the same as the last digit).\r
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\n" ); document.write( "\n" ); document.write( "The total number of possible arrangements is then 1 * 4 * 3 = 12\r
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\n" ); document.write( "\n" ); document.write( "The possibilities are:\r
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\n" ); document.write( "\n" ); document.write( "724
\n" ); document.write( "726
\n" ); document.write( "732
\n" ); document.write( "734
\n" ); document.write( "736
\n" ); document.write( "742
\n" ); document.write( "746
\n" ); document.write( "752
\n" ); document.write( "754
\n" ); document.write( "756
\n" ); document.write( "762
\n" ); document.write( "764
\n" ); document.write( " \n" ); document.write( "
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