document.write( "Question 1058255: The digits 3,4,5,6,7, and 8 are randomly arranged to form a three-digit
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Algebra.Com's Answer #673295 by Edwin McCravy(20055)\"\" \"About 
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The digits 3,4,5,6,7, and 8 are randomly arranged to form a
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document.write( "The solution above is incorrect.  He did not choose the MOST\r\n" );
document.write( "RESTRICTIVE digit first, and got 12 ways for the numerator,\r\n" );
document.write( "which is incorrect.  Also he did not find the probability.\r\n" );
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document.write( "Here's the correct solution:\r\n" );
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document.write( "We find the number of even three-digit numbers greater than\r\n" );
document.write( "800 with all different digits taken from 3,4,5,6,7,8\r\n" );
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document.write( "The last digit is the MOST RESTRICTIVE, since it must be even.\r\n" );
document.write( "so we choose it first:\r\n" );
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document.write( "We can choose the last digit any of 2 ways, as 4 or 6. \r\n" );
document.write( "[We can't choose 8 because we must save it for the first\r\n" );
document.write( "digit, since the number must be greater that 800].\r\n" );
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document.write( "We can then choose the first digit 1 way, as 8.\r\n" );
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document.write( "We can then choose the middle digit as any of the remaining 4 digits.\r\n" );
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document.write( "So that's 2∙1∙4 = 8 ways.\r\n" );
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document.write( "834, 836, 846, 854, 856, 864, 874, 876\r\n" );
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document.write( "So the numerator of the desired probability is 8.\r\n" );
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document.write( "The denominator is the number of permutations of 6 digits taken\r\n" );
document.write( "3 at a time or 6P3 = 120. Or do it this way:\r\n" );
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document.write( "Choose the 1st digit 6 ways, the 2nd digit 5 ways, the 3rd digit 4 ways,\r\n" );
document.write( "which is 6∙5∙4 = 120.\r\n" );
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document.write( "So the denominator of the desired probability is 120.\r\n" );
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document.write( "Answer is 8 ways out of 120 or 8/120 which reduces to 1/15.\r\n" );
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document.write( "Edwin
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