document.write( "Question 1058237: A $5000 investment that grows at annual rate of 6% can be modeled by the function:
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document.write( "y = 5000 (1.06)x
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document.write( "a) Determine the value of the investment after 20 years.
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document.write( "b) How long would it take for the investment to double? Use your graphing calculator and show
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document.write( " window dimensions and graph.
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document.write( "c) c) How long would it take the investment to double using the rule of 72? Explain any differences. \n" );
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Algebra.Com's Answer #673290 by stanbon(75887) ![]() You can put this solution on YOUR website! A $5000 investment that grows at annual rate of 6% can be modeled by the function: \n" ); document.write( "y = 5000 (1.06)^x \n" ); document.write( "a) Determine the value of the investment after 20 years. \n" ); document.write( "y = 5000*1.06^20 = 16035.68 \n" ); document.write( "------------------------------------ \n" ); document.write( "b) How long would it take for the investment to double? Use your graphing calculator and show window dimensions and graph. \n" ); document.write( "Solve:: \n" ); document.write( "2 = 1.06^x \n" ); document.write( "x = log2/log1.06 = 11.9 years \n" ); document.write( "-------------------------------------- \n" ); document.write( "c) c) How long would it take the investment to double using the rule of 72? Explain any differences. \n" ); document.write( "Don't know any rule of 72. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------- \n" ); document.write( " |